00:01
We can calculate electric field intensity with the help of coulomb's law.
00:05
So, electric field intensity at point e due to small element of charge de on the ring is equals to de is equals to k multiply dq divided by r square where k is coulomb's constant, dq is the charge on the small element of the ring and r is the distance between the element and the point p.
00:28
Since the e ring has uniform line charge, so we can express dq in terms of pi and length.
00:43
So, here dq will be equals to pi multiply dl where dl is the length of the element.
00:49
We can also express r in terms of h and distance between the element.
00:54
So, here r will be equals to square root of b square plus h square.
01:01
Putting all the value together we will get de is equals to k multiply pi multiply dl divided by b square plus h square.
01:15
Next we need to find the total electric field intensity at point p due to all the element of the ring.
01:20
We can do this by integrating de over the entire ring.
01:27
So, here e is equals to integral de.
01:32
Since the ring is symmetric about z axis, we can use cylindrical coordinate to perform the integration...