2. A rocket launched vertically expels mass at a constant rate equal to \( 0.05 \mathrm{mo} \mathrm{kg} / \mathrm{s} \), where \( m_{o} \) is its initial mass. The exhaust velocity of the gases relative to the rocket is 5 \( \mathrm{km} / \mathrm{s} \). Find the velocity \& the height of the rocket after 10 s. 3. A rocket ascends from rest in a uniform qravitational field by eiecting exhaust gases
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The momentum of the expelled gases is given by the mass of the gases times their velocity. The mass of the gases expelled per second is 0.05mo kg/s and their velocity is 5 km/s = 5000 m/s. Therefore, the force exerted by the rocket is (0.05mo kg/s)(5000 m/s) = Show moreā¦
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