Question

2. Active Second Order Butterworth Circuit Show that the following circuit has the transfer function shown. Design the circuit such that it has a unity gain and cutoff frequency of 1000 rad/sec and $C = 1\mu F$. Plot the Bode plot in MATLAB and then simulate the frequency response with the AC Sweep tool in Multisim #1/4#3 $H(s) = \frac{1/RC}{s^2 + 1/RC}$ $V_{in} - V^+ = \frac{V^+ - 0}{\frac{R}{R} + \frac{1}{sC}} \approx 0$ $\frac{V_{in} - V^+}{R} = sCV^+$ $V_{in} - V^+ = sRCV^+$ $V_{in} = (1 + sRC)V^+$

          2. Active Second Order Butterworth Circuit
Show that the following circuit has the transfer function shown. Design the circuit such that
it has a unity gain and cutoff frequency of 1000 rad/sec and $C = 1\mu F$. Plot the Bode plot in
MATLAB and then simulate the frequency response with the AC Sweep tool in Multisim
#1/4#3
$H(s) = \frac{1/RC}{s^2 + 1/RC}$
$V_{in} - V^+ = \frac{V^+ - 0}{\frac{R}{R} + \frac{1}{sC}} \approx 0$
$\frac{V_{in} - V^+}{R} = sCV^+$
$V_{in} - V^+ = sRCV^+$
$V_{in} = (1 + sRC)V^+$

2. Active Second Order Butterworth Circuit
Show that the following circuit has the transfer function shown. Design the circuit such that
it has a unity gain and cutoff frequency of 1000 rad/sec and C = 1μ F. Plot the Bode plot in
MATLAB and then simulate the frequency response with the AC Sweep tool in Multisim
#1/4#3
H(s) = (1/RC)/(s^2 + 1/RC)
Vin - V^+ = (V^+ - 0)/((R)/(R) + (1)/(sC))≈ 0
(Vin - V^+)/(R) = sCV^+
Vin - V^+ = sRCV^+
Vin = (1 + sRC)V^+

Added by Mohamed M.

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