$2 Al(s) + 3 Br_2(l) \rightarrow Al_2Br_6(s)$ What mass of $Br_2$, in grams, is required for complete reaction with 2.56 g of Al? What mass of white, solid $Al_2Br_6$ is expected?
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Molar mass of Al = 26.98 g/mol Molar mass of $Br_2$ = 2 * 79.90 g/mol = 159.80 g/mol Molar mass of $Al_2Br_6$ = 2 * 26.98 g/mol + 6 * 79.90 g/mol = 53.96 + 479.4 = 533.36 g/mol Show more…
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