2. An association of City Mayors conducted a study to determine the average number of times a family went to buy necessities in a week. They found that the mean is 4 times in a week. A random sample of 20 families were asked and found a mean of 5 times in a week and a standard deviation of 2. Use \( 5 \% \) significance level to test that the population mean is not equal to 4. Assume that the population is normally distributed. Null hypothesis: Symbol: Alternative hypothesis: Symbol: Level of Significance :
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The null hypothesis (\(H_0\)) is that the population mean number of times families go to buy necessities in a week is equal to 4. The alternative hypothesis (\(H_1\)) is that the population mean is not equal to 4. Therefore, we have: - \(H_0: \mu = 4\) - \(H_1: Show more…
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