Block A with a mass of 100 kg and block B with a mass of 200 kg are joined by an inextensible cable, Fig. 2. The coefficient of kinetic friction between block A and the plane is 0.2. If the system is released from rest, determine the velocity of block A after it has moved to the right 1 m. Neglect the mass of the cable and the pulley.
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The weight of block B (200 kg * 9.8 m/s^2 = 1960 N) is pulling the system downwards, while the weight of block A (100 kg * 9.8 m/s^2 = 980 N) and the frictional force on block A (0.2 * 980 N = 196 N) are resisting this motion. So, the net force is 1960 N - 980 N - Show more…
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