2 C2H4 + 6 O2 --> 4 CO2 + 4 H2O From the above reaction, how many moles of O2 are required for the complete combustion of 44.88 g of C2H4? a. 1.3 Ă—102 mol b. 3.00 mol c. 4.8 mol d. 11.25 mol
Added by James S.
Step 1
To do this, we'll use the molar mass of C2H4. The molar mass of C2H4 is (2 * 12.01) + (4 * 1.01) = 28.06 g/mol. Now, we can find the number of moles of C2H4: moles of C2H4 = (44.88 g) / (28.06 g/mol) = 1.6 mol From the balanced equation, we can see that 2 moles Show more…
Show all steps
Your feedback will help us improve your experience
Adi S and 95 other Chemistry 101 educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
2 C2H4 + 6 O2 --> 4 CO2 + 4 H2O From the above reaction, if 2.0 mol of CO2 are produced, how many mols of O2 were reacted? a. 6 mol b. 3 mol c. 3.5 mol d. 7.5 mol
Anna D.
2) C2H4 + 3 O2→ 2 CO2 + 2 H2O a) If you react 960 grams of O2, how many moles of CO2 will be produced? b) If you start with 45 grams of ethylene (C2H4), how many grams of carbon dioxide will be produced?
Ronald P.
Recommended Textbooks
Chemistry: Structure and Properties
Chemistry The Central Science
Chemistry
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD