00:01
Hello students, so for this question we have a reaction m2o which upon decomposition forms 2m plus 1 by 2 o2.
00:11
Now the delta h formation and the entropy for all these reactant products are given.
00:19
So, let me write it like this delta hf for the m2o it is 16 .45.
00:28
So, it is in kj per mole.
00:33
For m it is 279 .90 and for o2 it is 0 and same for the entropy which is in joule per kelvin mole inverse.
00:49
So, for m2o it is 23 .20 for m it is 6 .41 and for oxygen it is 0.
01:00
So, we have to calculate the delta g of the reaction.
01:04
For that we will calculate first the delta h not for this reaction which is equals to summation of delta h formation of the products minus summation of delta h formation of the reactants.
01:18
So, for the product we have m and o2.
01:21
So, we will not consider o2 because the delta hf for o2 is 0 and s is also 0.
01:27
So, product we have m.
01:29
So, we will write here 2 into delta hf of m minus delta hf of m2o.
01:37
Now the delta hf of m is 279 .90 into 2 minus 16 .45...