2. Calculate isoelectric point (pI) of following peptide. Gly-Glu-Ala-Lys-Tyr-Arg-Leu pKa N terminal NH3+ 9.6 Glu 4.25 Lys 10.53 Arg 12.48 C terminal COOH 2.36 3. Protein X has a 100 nM affinity for ligand Q. How much of ligand Q is required for the following fractions of protein X to exist in the bound state? a) 0.10 b) 0.30 c) 0.50 d) 0.90 Protein Z also binds ligand Q. At a concentration 200 mM Q, of protein Z is 70% bound. Which protein (X or Z) has a greater affinity for ligand Q?
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The peptide sequence is: Gly-Glu-Ala-Lys-Tyr-Arg-Leu The pKa values are: N-terminal NH3+ (9.69), Glu (4.25), Lys (10.53), Arg (12.48), C-terminal COOH (2.36) To calculate the pI, we need to find the pH at which the net charge of the peptide is zero. We can do Show more…
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