2. Charges of 1x10?? and 2x10?? C are located at the two lower vertices of the triangle, as shown in the figure below (a) Find the E field at the third vertex, point P. (b) Find the force on a positive charge 1.5x10?? C placed at P.
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The electric field at P due to the 1 x 10^-4 C charge is E1 = k(1 x 10^-4)/r^2 and the electric field at P due to the 2 x 10^-4 C charge is E2 = k(2 x 10^-4)/r^2. Since the charges are at the same distance from P and the electric field is a vector quantity, we Show more…
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