00:01
Hi, here in this given problem we have to find the total impedance, net impedance of the given combination of inductors.
00:15
Okay, so first of all here this is the first inductor, 25 micro henry, then another one, 18 micro henry.
00:30
In series with it, directly in series, that is 12 micro -henry.
00:40
Then in front of this 18 micro -henry, this is 38 micro -henry.
00:50
Here in parallel with the 12 micro -henry, this is 75 micro -henry.
01:00
Then diagonally this is 20 micro henry then in parallel with this 75 micro henry here this is 30 micro henry then in front of this 25 micro henry here this is 15 micro henry and at diagonally again this is 60 micro henry this is terminal b so we have to find net inductance across the terminals a and b l ab we have to find so using the rules of series and parallel combination and the same rules are used here as we use in the combination of resistors then starting from here 18 and 12 micro henry are in series so l s 1 this is the first series of the circuit and that is 18 plus 12 micro henry means it comes out to be equal to 30 micro henry now this 30 micro henry it is in parallel with 20 micro henry so so first parallel combination of the two inductors, 20 and 30, the shortcut 20 into 30 divided by 20 plus 30.
02:49
This is the method.
02:51
This is the trick which we can use if only two inductors are in parallel combination.
02:57
So this is 600 divided by 50 and it comes out to be equal to 12 micro, micro, and so, this is 600.
03:06
Now this 12 micro henry complete it is in series again with 38 micro henry...