00:01
Hi, in this question, we have the series circuit, which is composed of a non -ideal inductor l, resistor r, having resistance 550 ohm, and an ac power supply.
00:14
If the voltage across each item is measured, and the results are vr equals to 8 .8 volt, vl equals to 6 .6 volt, and vt equals to 12 .1 volt, then we have to draw the phasor diagram of the circuit.
00:34
And from this diagram, we have to find the numerical values of the inductance and internal resistance, such that the frequency is given as 50 hertz.
00:45
So first of all, if we assume that the inductance is l, and internal resistance is small l, then the net resistance of this circuit will be capital r plus small r.
01:05
So the phasor diagram can be drawn as, so if this is our current, this is our voltage, so we'll have vl in this direction.
01:25
So we'll have vl in this direction.
01:28
We'll have vt in this direction.
01:31
And we'll have vr plus r in this direction.
01:39
Now, as vr is given as 8 .8 volt, therefore, current i can be calculated as vr divided by resistance r.
01:58
So this will be 8 .8 divided by 550, which gives the value of current i as 0 .016 ampere...