Question

2. Draw the Fischer projection for each of the given molecules. Number the carbons in the longest chain in each drawing. a) (R)-3-methylhexane and its enantiomer b) (3R,4S)-3,4-dimethylhexane and its enantiomer c) (3S,4R)-3-bromo-4-chlorohexane and its enantiomer d) (2S,3S,4S)-2,3,4-trichloroheptane and its enantiomer e) (S)-2-chloro-1,1,1-trifluoropropane and its enantiomer

          2. Draw the Fischer projection for each of the given molecules. Number the carbons in the longest
chain in each drawing.
a) (R)-3-methylhexane and its enantiomer
b) (3R,4S)-3,4-dimethylhexane and its enantiomer
c) (3S,4R)-3-bromo-4-chlorohexane and its enantiomer
d) (2S,3S,4S)-2,3,4-trichloroheptane and its enantiomer
e) (S)-2-chloro-1,1,1-trifluoropropane and its enantiomer

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2. Draw the Fischer projection for each of the given molecules. Number the carbons in the longest
chain in each drawing.
a) (R)-3-methylhexane and its enantiomer
b) (3R,4S)-3,4-dimethylhexane and its enantiomer
c) (3S,4R)-3-bromo-4-chlorohexane and its enantiomer
d) (2S,3S,4S)-2,3,4-trichloroheptane and its enantiomer
e) (S)-2-chloro-1,1,1-trifluoropropane and its enantiomer

Added by Andr-S S.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

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Solved by Expert Sri K

06/08/2022

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Step 1: Draw the Fischer projection for each of the given molecules and number the carbons in the longest chain in each drawing. Show more…

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Transcript

00:01 Hello, hi students, let me explain you the question.

00:03 Here we have to draw the fisher projection.

00:07 Fisher projection for the given molecules.

00:12 And also here we have to number the corbans in the longest chain.

00:19 So in the longest chain for each drawing, we have to number the corbons, number the corbons.

00:28 So here, what is meant by fisher projection? so fisher projection, it is nothing but the two -dimensional arrangement of, or two -dimensional representation of two -dimensional representation.

00:44 So the particular representation, the two -dimensional representation of a molecule, in projection form, in projection form of a three -dimensional organic molecule, three -dimensional, organic molecule so that is fish hair projection so here for all the molecules given here we have to draw the fissure projection and also we have to number the carbon in the longest chain for each drawing then coming to the then coming to the here are the given molecules we have to consider the r and s configuration what is meant by our configuration what is meant by if the higher priority groups, for example, this is the higher priority groups.

01:41 So the first higher priority group, it is numbered as 1, then next priority group it is numbered as 2, and next priority group it is numbered as 3, and next like this.

01:55 So if we draw a arrow from the highest priority to lowest priority, if the arrow it is anticlockwise, then it is yes, configuration yes configuration whereas if the arrow it is that means the priority groups they are arranged in the clockwise direction so for example bromine here of methyl group and here it is here oxygen and here hydrogen so whenever we see the priority groups how they are arranged so they are arranged in the clockwise direction.

02:39 They are arranged in clockwise direction.

02:43 So it is our configuration.

02:47 So it is our configuration.

02:49 So we have to consider these...

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