00:01
In this given problem, a mass is attached to a string which goes over through a pulley.
00:09
So this mass, let's call it mass 1, is sliding on the table, attached to a string that goes over the pulley.
00:18
And on the other hand, we have another mass that is called m2, which is hanging down.
00:30
So this mass, due to the gravitational force or a weight of this mass, it's pulled down with the force of m2g.
00:47
So when it goes down, it produces an acceleration, let's call it a.
00:55
And there is an opposite force acting on a string, which is the tension of the string.
01:00
This tension is transmitted through the string to mass 1 and mass 1 is attracted by the same acceleration as a mass 2a.
01:13
And there is a force of t newton, sorry, a tension on mass 1 due to the weight of m2g.
01:30
So we can write an equation for mass 2, which is mass 2 times gravitational acceleration, the force downward minus tension will be equal to mass 2 times the acceleration of m2.
01:47
And we see the forces on mass 1 due to its weight cancels out with the normal force.
01:56
Let's say downward force here is m1g, and this weight is cancelled by its normal force upward.
02:03
There's only a tension for that's acting on a mass 1.
02:06
So t is equal to m1a...