2. Fill in each box with the expected organic product of the...

2. Fill in each box with the expected organic product of the indicated multistep transformation. Be sure that the products you draw take into account all steps of the transformation, including workup steps! You may ignore stereochemistry. 1. NaCN, EtOH, 80 °C 2. LiAlH4, Et2O 3. H+ workup 1. H3O+ 2. NaBH4, MeOH 1. NaOH, H2O 2. H+ workup 3. LiAlH4, Et2O 4. H+ workup 5. CrO3, pyridine 1. HNEt pH 5 2. LiAlH4, Et2O 3. H+ workup

Transcript

00:01 Hello students hope you are doing great in this question we are given few organic reactions and we have to find out the products of step by step so the first reaction is this this molecule reacts with sodium cyanide in the first step sodium sign in sodium cyanide cn is a nucleophile carbonal carbon is electrophilic in nature so this will attack and the electrons of fibrin will move to the oxygen so there will be formation of a negative charge on oxygen like this.

00:39 Here we have cn group and the 5 member ring as it is.

00:45 In the second step it reacts with lithium aluminum hydride.

00:49 Lithium aluminum hydride is a reducing agent.

00:51 It will reduce this double bond and will convert it into single bond by addition of hydrogen.

00:58 So this double bond is converted into hydrogen.

01:01 Here we have cn and here we have oem.

01:06 Minus by the action of lithium aluminum hydride this cn is also converted into ch2 nh2 so here there will be ch2 and nh in the last step this o minus will take up a proton and will form the oh bond there so the final product that we have here is this here we have oh and ch2 nh2 in the next reaction we we are given a tertiary amine in a cyclic form like this with a double bond over here and a ph group here.

01:57 Here in the first step it reacts with h3o plus and this lone pair of electron will take a proton from this.

02:05 So there will be formation of a positive charge on nitrogen like this.

02:10 The double bond stays as it is.

02:13 Here we have ph, h plus and positive charge on the nitrogen.

02:18 Nitrogen plus h2o.

02:23 This then reacts with sodium borohydride and by the action of sodium borohydrate this double bond will be converted into single bond...

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