00:01
Hi, in this question they are asking us to calculate the horizontal and vertical component of force at pc in terms of the tension in this pulley t.
00:11
So the radius of the pulley r is given as 0 .75 meter.
00:17
So first of all we'll see the free body diagram of pc and then we'll analyze it.
00:25
So here first of all let us draw this pc and over here we have a pulley.
00:35
So the radius of pulley is 0 .75 and 3 meter is the distance from the center.
00:41
So if we'll see we'll get this distance as 2 .25 and from here we have 3 meters.
00:49
So if we add the radius so we'll get this distance as 3 .75.
00:54
So in this direction we'll have bx in this direction we'll have by.
01:00
Similarly in this particular direction we'll have cx and downwards we'll have cy.
01:07
So the tension will be in this direction t and in the downward direction also we'll have a tension t.
01:15
So if we see net moment about b that should be zero as it is at equilibrium.
01:22
So summation of net moment at b should be zero.
01:26
So we can write t into 2 .25 plus t into 2 minus cy into 6 as equals to zero.
01:38
So from here we'll get the value of cy as 0 .708 times t.
01:46
Now we'll see that the summation of force in y direction will also be zero.
01:55
So we can write by minus t plus cy as equals to zero or by will be equals to 1 minus 0 .708 times t.
02:07
So we have just kept the value of cy which gives the value of by as 0 .292 into t.
02:18
Now moving further we can also write that the summation of f in x direction will be zero.
02:29
Hence we'll have bx plus cx plus t as equals to zero.
02:36
So we'll just mark this as equation 1...