00:01
Hi there, so for this problem, we need to find the ad -set magnetic field, a distant seat above the center of a square loop of side w current -occurrant -i.
00:13
So we need to verify that it reduces to the feel of a diapol with the appropriate diapult moment when seed is much greater than the side w.
00:30
So in this case, we know that the fee, we have the situation in this case shown in this figure.
00:40
As you can see, this is the point where we are measuring the magnetic field.
00:47
And then we have some lamps in here.
00:50
We have the angle fee, the angle theta 2.
00:54
And then we have the side in here, which is w .u divided by 2 because we know that this whole length in here is w and then we know that the field of one side is given by the equation 5 .35 with x that can be written as the square root of this is this distancing here that is the square of seed the square root of the square of seed plus w divided by two to the square and sine of theta 2, in this case of theta 2, is equal to the minus sine of theta 1, that we can write by trigonometry.
01:53
In this case, this is going to be w divided by 2, and this divided by the radius that we know the distance to the point gc2 square plus w squared divided by 2.
02:20
Oh, sorry, i forgot that this whole term is to the square.
02:26
Sorry.
02:27
Okay, so we have this.
02:30
Now, we can write that the magnetic field, the magnitude of the magnetic field, is equal to mu -sup zero times the current, divided by 4 times pi.
02:42
And this times we will have in the denominator, we will have the product between c2 square plus w squared divided by 4.
02:56
And this times c22 plus w squared plus w squared divided by 2.
03:06
Oh, this is this one in here.
03:08
Sorry, the last one in here, it is c squared divided by 2...