00:01
Hello, here five resistors are connected as shown in the task and first we have to find the equivalent resistance.
00:08
Let's do this.
00:09
But to do this we have to draw this rocket.
00:12
Let's start with resistance r at point a.
00:19
And here that is connected in cri to the parallel connection of the resistance of 120 oms.
00:28
And then it's connected and another branch of this parallel connection is parallel connection of 40 oms resistance with which is in parallel with r and 5 oms which are in civ so that's equivalent circuit and let's and here are is 55 oms now let's then calculate the equivalent resistance so first of all let's here we'll label for example this part as 1 -2 and therefore r1 -2 is r plus 5 oms which is 60 ooms now let's find the connection between points, for example, 3 and 4.
01:47
R3 -4 is 40 oms times 60 oms divided by the sum of 40 and 60 oms.
02:05
That is 24 oms.
02:11
Now we can find the equivalent resistance here.
02:17
Equivalent resistance is r plus.
02:24
120 oms multiply by 24 oms divided by the sum of 120 and 24 oms.
03:13
So that is 5 oms plus 20 oms which is 25 oms and that is the equivalent resistance.
03:24
Now let's move on to question b in question b we have to find the power of the 5 -oom resistor.
03:38
It means that we have to find current which flows through this resistor, that is we label as i -5.
03:48
First of all, let's find the total current...