?????? 2 :Given the probability mass function of the random variable \( X \) as \begin{tabular}{llllll} 4 & 3 & 2 & 1 & 0 & \( x \) \\ 0.421 & 0.198 & 0.143 & 0.131 & 0.107 & \( f(x) \) \end{tabular} \( \qquad \) The second moment is 1.957975 . A 9.221 .B 0.143 .C 2.695.D
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The PMF is given as: - \( P(X = 4) = 0.421 \) - \( P(X = 3) = 0.198 \) - \( P(X = 2) = 0.143 \) - \( P(X = 1) = 0.131 \) - \( P(X = 0) = 0.107 \) Show more…
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