The relationship between the two is given by:
$$T_{1/2} = \frac{ln(2)}{\lambda}$$
So,
$$\lambda = \frac{ln(2)}{T_{1/2}}$$
Given $T_{1/2} = 4.468 \times 10^9$ years, we need to convert this to seconds:
$T_{1/2} = 4.468 \times 10^9 \text{ years} \times 365.25
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