00:01
So in this question we use a anova table.
00:05
Anova.
00:08
So first is the treatment.
00:11
So in the treatment there is a two value k is the treatment number of treatment 3.
00:18
So sum of square of for treatment sum of square of treatment is equal to 1100.
00:25
So then is error.
00:33
So again total number of experimental unit.
00:40
So n is equal to 12 plus 15 plus 20.
00:46
There is a three treatments.
00:48
So the answer is 47.
00:52
Total number of experiment.
00:54
And total sum of square s s 3 is equal to 1800.
01:04
So let calculate the degree of freedom of the treatment.
01:09
So this is a given.
01:21
So next we calculate the degree of freedom treatment and error.
01:36
So the treatment is degree of freedom is dft is equal to k minus 1.
01:46
Degree of freedom for treatment is dft.
01:51
So we say that degree of freedom for treatment.
02:06
So degree of freedom dfe is equal to n minus k.
02:14
So 47 minus 3.
02:17
The answer is 44.
02:20
K minus 1 is equal to 3 minus 1 is equal to 2.
02:26
So then we find the mean square.
02:31
Mean square calculate...