2 In a hydraulic press a force of 20 N is applied to a piston of area 0.20 m2. The area of the other piston is 2.0 m2. What is a the pressure transmitted through the liquid, b the force on the other piston?
Added by Diane M.
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We can use the formula: Pressure (P) = Force (F) / Area (A) a) For the first piston, we have: Force (F1) = 20 N Area (A1) = 0.20 m² So, the pressure transmitted through the liquid is: P = F1 / A1 Show more…
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The diameter of the large piston of a hydraulic press is $20 \mathrm{~cm}$, and the area of the small piston is $0.50 \mathrm{~cm}^{2}$. If a force of $400 \mathrm{~N}$ is applied to the small piston, $(a)$ what is the resulting force exerted on the large piston? (b) What is the increase in pressure underneath the small piston? ( $c$ ) Underneath the large piston?
The diameter of the large piston of a hydraulic press is $20 \mathrm{~cm}$, and the area of the small piston is $0.50 \mathrm{~cm}^{2}$. If a force of $400 \mathrm{~N}$ is applied to the small piston, (a) what is the resulting force exerted on the large piston? (b) What is the increase in pressure underneath the small piston? ( $c$ ) Underneath the large piston?
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