Given:
Initial voltage, \( V_0 = 50 \) V
Final voltage, \( V = 15 \) V
Equivalent capacitance, \( C_{eq} = 4 \) mF
Equivalent resistance, \( R_{eq} = 8 \times 10^3 \) ohm
Using the formula \( V = V_0 \times e^{-\frac{t}{R_{eq} \times C_{eq}}} \), we can solve for
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