Question

2 Loop Analysis Solve the following using loop analysis. This means find the currents in each loop. Each is worth 1.25 marks, the question is worth 10 marks in total. Note that the control voltage $v_x$ for the dependent voltage source $\beta v_x$ is through the bottom-right resistor as shown. It is probably necessary to use a computer to solve the matrix equation. Hint: Many of the node voltages have simple relationships to other nodes. If you hate matrices, you can make use of these relationships to reduce the problem to a $3 \times 3$ matrix. However, since you will probably solve the matrix on a computer anyway, you might find is simpler to write out the full $8 \times 8$ matrix. Where $R_a = 1k\Omega$, $R_b = 3.5k\Omega$, $R_c = 3.5k\Omega$, $V = 8V$, $I = 1.3mA$, $\beta = 2.4$

          2 Loop Analysis
Solve the following using loop analysis. This means find the currents in each loop. Each is worth 1.25 marks,
the question is worth 10 marks in total. Note that the control voltage $v_x$ for the dependent voltage source $\beta v_x$ is
through the bottom-right resistor as shown.
It is probably necessary to use a computer to solve the matrix equation.
Hint: Many of the node voltages have simple relationships to other nodes. If you hate matrices, you can make use
of these relationships to reduce the problem to a $3 \times 3$ matrix. However, since you will probably solve the matrix on
a computer anyway, you might find is simpler to write out the full $8 \times 8$ matrix.
Where $R_a = 1k\Omega$, $R_b = 3.5k\Omega$, $R_c = 3.5k\Omega$, $V = 8V$, $I = 1.3mA$, $\beta = 2.4$

2 Loop Analysis
Solve the following using loop analysis. This means find the currents in each loop. Each is worth 1.25 marks,
the question is worth 10 marks in total. Note that the control voltage vx for the dependent voltage source β vx is
through the bottom-right resistor as shown.
It is probably necessary to use a computer to solve the matrix equation.
Hint: Many of the node voltages have simple relationships to other nodes. If you hate matrices, you can make use
of these relationships to reduce the problem to a 3 × 3 matrix. However, since you will probably solve the matrix on
a computer anyway, you might find is simpler to write out the full 8 × 8 matrix.
Where Ra = 1kΩ, Rb = 3.5kΩ, Rc = 3.5kΩ, V = 8V, I = 1.3mA, β = 2.4

Added by Lori H.

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