00:01
We are asked to find enthalpy change for the process involved in two moles of an ideal gas, expanding isothermally and reversibly from 2 to 20 liters.
00:15
Okay, so we're going to use the following equation.
00:19
First, we have to find work.
00:20
I'm using a really bad pen right now because mine is charging.
00:24
Equals negative 2 .303 times n -r -t times the log of v -final minus v -i.
00:40
So we are given two moles, so let me just go ahead and plug this in here.
00:45
This is a little hard.
00:46
W equals negative 2 .303 times n, which we had as two moles.
00:59
I'm going to leave my units out.
01:00
Times r, which will use 8 .314, and that's lkpa over kmo, or joules, probably joules per kmo.
01:15
Then i've got my temperature, nrt, which is 37 plus, why isn't this going? 37 plus 273, which is 300, times the log of 203.
01:37
Over two.
01:38
That's the log of 10, so that's going to be one...