00:01
Hello students from the question, here they given that for female students it is x follows the normal distribution of 65 ,3 .5.
00:14
This is our mean mu and this is our standard deviation sigma.
00:19
Then for males which is y follows the normal distribution of 70 ,4.
00:26
This is our mean and this is our standard deviation.
00:30
Now here for the subpart a, what is the probability of that randomly selected female student? so p of x less than 60 inches tall.
00:41
Now here we need to find that the probability of x minus mu divided by sigma that is equal to 60 minus 65 divided by 3 .5.
00:54
It is equal to probability of z less than 1 .43 which is minus.
01:03
So here we conclude that the z score which is equal to minus 1 .43.
01:11
Now for the subpart b, here what is the probability of randomly selected male height is more than 71 inches.
01:29
Here we need to find the z score that is x minus mu, y minus mu by sigma 71 minus 70 divided by 4 which is equal to here z score as 0 .25.
01:46
Then for the subpart c, percentage of female students are between.
01:51
So here probability of 64 less than x less than 77.
01:56
It is equal to the probability of 64 minus 65 divided by 3 .5 less than x minus mu by sigma less than 77 minus 65 divided by 3 .5...