00:01
Hello, so in this question we need to draw the structure of the following five molecules.
00:06
So one by one we will solve the structure of the following according to iopc nomenclature.
00:11
The first one is two pentine.
00:14
So it consists of five carbon, a triple bond at second position.
00:19
So if we draw first five carbons, then at second position there is a triple bond.
00:26
Now we will write the hydrogens, that is cs3, ch2, here it will be cs3.
00:34
So this will be the structure of 2 pentine.
00:37
On 2 carbon, it consists of 2 -bromo 1 butene.
00:41
So at second position, bromey and there is a double bond on 1 carbon.
00:46
So it will be having the structure as cs3, ch2, cbr, double bond, th2.
00:55
This will be the structure of 2 -bromo 1 butene.
00:59
For 3, it is 1 -3 diomethyl cycloheg.
01:02
There is a cyclohexene molecule.
01:05
So first we will draw cyclohexene...