In a Rutherford scattering experiment a target nucleus has a diameter of 1.20 x 10^-14 m. The incoming particle has a mass of 6.64 x 10^-27 kg. What is the kinetic energy of an alpha particle that has a de Broglie wavelength equal to the diameter of the target nucleus? Ignore relativistic effects.
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626 \times 10^{-34} \, \text{J s}\) \(\lambda = 1.2 \times 10^{-14} \, \text{m}\) Substitute the values: \(p = \frac{6.626 \times 10^{-34}}{1.2 \times 10^{-14}} = 5.522 \times 10^{-20} \, \text{kg m/s}\) Show more…
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