Question

. (2 points) Recall that the thermal voltage is a function of the temperature of the junction (in Kelvin), Boltzmann’s Constant 𝑘 = 1.3806 × 10−23[J/K], and the electron charge 𝑞 = 1.6022 × 10−19[C], 𝑉𝑇 = 𝑘𝑇 𝑞 a. Calculate the value of the thermal voltage 𝑉𝑇 at -40°C, 0°C, 20°C, +25°C, and +150°C

Name: 2 points recall that the thermal voltage is a function of the temperature of the junction in kelvin boltzmanns constant k 13806 1023jk and the electron charge q 16022 1019c vt kt q a calcula 29698
Uploaded: 2024-11-27T11:44:42-08:00
Duration: 4 min 43 s
Channel: Shu Naito
Description: 2 points recall that the thermal voltage is a function of the temperature of the junction in kelvin boltzmanns constant k 13806 1023jk and the electron charge q 16022 1019c vt kt q a calcula 29698

          . (2 points) Recall that the thermal voltage is a function of the temperature of the junction (in Kelvin), Boltzmann’s Constant 𝑘 = 1.3806 × 10−23[J/K], and the electron charge 𝑞 = 1.6022 × 10−19[C], 𝑉𝑇 = 𝑘𝑇 𝑞 a. Calculate the value of the thermal voltage 𝑉𝑇 at -40°C, 0°C, 20°C, +25°C, and +150°C

Added by Felipe R.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Shu Naito

11/27/2024

Step 1

3806 \times 10^{-23} \, \text{J/K} \) (Boltzmann's constant) - \( q = 1.6022 \times 10^{-19} \, \text{C} \) (electron charge) - \( T \) is the temperature in Kelvin. We need to convert the given temperatures from Celsius to Kelvin using the formula: \[ T(K) = Show more…

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. (2 points) Recall that the thermal voltage is a function of the temperature of the junction (in Kelvin), Boltzmann’s Constant 𝑘 = 1.3806 × 10−23[J/K], and the electron charge 𝑞 = 1.6022 × 10−19[C], 𝑉𝑇 = 𝑘𝑇 𝑞 a. Calculate the value of the thermal voltage 𝑉𝑇 at -40°C, 0°C, 20°C, +25°C, and +150°C