00:01
The question says to make the major products in each of the cases.
00:06
The five cases given here, five reactants.
00:09
And we have to make the major products.
00:12
So let's see the explanation for it.
00:15
So first of all, we will see for the part here.
00:22
The reactant is this, which in the presence of nos cs2, cs3, and second, it is s2.
00:34
It will form the major product, which will be, and here it will be o -c -s -2.
00:44
To ch.
00:50
Now we see for the second product, the second part here, this is, and if we see the product after this we are getting br will attach here.
01:10
So if we see here, first of all, this is one, two, three, four, five and six, six carbons and a double bond.
01:20
So what is it? it is hexene...