Question

2. Show the content of registers A, B, Q, and SC during the decimal multiplication of (a) 470 x 152 and (b) 999 x 199. Assume three-digit registers and take the second number as the multiplier.

          2. Show the content of registers A, B, Q, and SC during the decimal multiplication of
(a) 470 x 152 and
(b) 999 x 199.
Assume three-digit registers and take the second number as the multiplier.

Added by Alexandria C.

Computer Science and Information Technology

Trishna Knowledge Systems 2018 Edition

Instant Answer

Solved by Expert Madhur L

11/08/2023

Step 1

We will assume that: - Register A holds the multiplicand (first number). - Register B holds the multiplier (second number). - Register Q will hold the result. - Register SC will be used as a shift counter. (a) 470 x 152 **Initialization:** - A = 470 - B = 152 - Show more…

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2. Show the content of registers A, B, Q, and SC during the decimal multiplication of (a) 470 x 152 and (b) 999 x 199. Assume three-digit registers and take the second number as the multiplier.

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Transcript

00:01 Hello student to perform the division of the given number by 1011 using an 8 bit dividend we need to simulate the process step by step.

00:11 The process involves shifting the dividend performing subtraction and updating the quotients.

00:16 So let's go through the step by step.

00:19 Let's go through the step one by one.

00:21 Number one initially the values in the registers are e, a, q, se.

00:28 So e is carry the dividend which is the given value and a is the divisor which is 1011.

00:37 Quotient initially is 0, 8 bit 0s and here se step counter is also 0 at the starting.

00:45 Now step 0, dividend is remain same, divisor remain same, quotient same, step counter is 0.

00:53 Now come to the step 1.

00:55 In the step 1 what is going on in the step 1 dividend.

01:01 So here se step counter will be incremented to 1.

01:06 Now come to the step 2.

01:08 In the step 2, dividend shift left because we are doing division so dividend will shift towards the left.

01:17 Divisor is this one so quotients updated with the bit from the previous step.

01:22 So here the quotient will also updated and here se will be incremented.

01:27 It comes to now it is the value of the step counter.

01:31 Now come to the step 3...

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