2 sin^2 x + sin x -1=0
Added by Danny B.
Step 1
Let y = sin x. Then, the equation becomes: 2y^2 + y - 1 = 0 This is a quadratic equation that we can solve using the quadratic formula: y = (-b ± √(b^2 - 4ac)) / 2a where a = 2, b = 1, and c = -1. Plugging in these values, we get: y = (-1 ± √(1 + 8)) / 4 y = Show more…
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