Question

2. Solve $2\sin^2\theta - 3\sin\theta + 1 = 0$ for $\theta$ in the interval $[0, 2\pi]$. 3. For a triangle with $\angle A = 45^\circ$, $a = 6$ and $b = 9$, use the Law of Sines to find $\angle B$. 4. In triangle ABC, $\angle A = 40^\circ$, $\angle B = 30^\circ$ and side $a = 12$ cm. Find side $b$

Name: 2 solve 2sin2theta 3sintheta 1 0 for theta in the interval 0 2pi 3 for a triangle with angle a 45circ a 6 and b 9 use the law of sines to find angle b 4 in triangle abc angle a 40circ angle 52221
Uploaded: 2022-12-16T20:51:16-08:00
Duration: 4 min 30 s
Channel: Gregory Higby
Description: 2 solve 2sin2theta 3sintheta 1 0 for theta in the interval 0 2pi 3 for a triangle with angle a 45circ a 6 and b 9 use the law of sines to find angle b 4 in triangle abc angle a 40circ angle 52221

          2. Solve $2\sin^2\theta - 3\sin\theta + 1 = 0$ for $\theta$ in the interval $[0, 2\pi]$.
3. For a triangle with $\angle A = 45^\circ$, $a = 6$ and $b = 9$, use the Law of Sines to find $\angle B$.
4. In triangle ABC, $\angle A = 40^\circ$, $\angle B = 30^\circ$ and side $a = 12$ cm. Find side $b$

2 solve 2sin2theta 3sintheta 1 0 for theta in the interval 0 2pi 3 for a triangle with angle a 45circ a 6 and b 9 use the law of sines to find angle b 4 in triangle abc angle a 40circ angle 52221

Added by Kathy T.

Introductory and Intermediate Algebra for College Students 4th

Robert Blitzer 4th Edition

Instant Answer

Solved by Expert Gregory Higby

12/16/2022

Step 1

Then the equation becomes $2x^2 - 3x + 1 = 0$. This is a quadratic equation. We can factor it as $(2x - 1)(x - 1) = 0$. Thus, $2x - 1 = 0$ or $x - 1 = 0$. This gives $x = \frac{1}{2}$ or $x = 1$. Since $x = \sin\theta$, we have $\sin\theta = \frac{1}{2}$ or Show more…

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2. Solve $2\sin^2\theta - 3\sin\theta + 1 = 0$ for $\theta$ in the interval $[0, 2\pi]$. 3. For a triangle with $\angle A = 45^\circ$, $a = 6$ and $b = 9$, use the Law of Sines to find $\angle B$. 4. In triangle ABC, $\angle A = 40^\circ$, $\angle B = 30^\circ$ and side $a = 12$ cm. Find side $b$