00:01
This problem wants us to use a calculator to solve the equation of the interval 0 less than or equal to theta less than 2 pi 4 5 plus secant of theta equal to 0.
00:10
And we are to use decimal notation and round our answers to three decimal places.
00:13
And what we will do to start is isolate our secant of theta by subtracting 5 to the right side.
00:19
So that's secant of theta equal to negative 5.
00:22
And what we need to realize now is that we're dealing with secant, which is the reciprocal of cosine.
00:26
So that's equivalent to 1 over cosine.
00:28
And cosine represents the x value.
00:31
And if we have 1 over an x value that's supposed to turn into negative 5, that means that our result needs to be something where x values are negative.
00:39
And x values are negative in the second and the third quadrant.
00:43
So what we're going to do to start is first find the solution in our first quadrant because that would be equivalent to our reference angle...