2. Solve for the Gravitational force between you and the Earth if you are 1ft away from the Earth. Mass of Earth \( =5.972 \times 10^{\wedge} 24 \mathrm{~kg} \) \[ F_{g}=G \frac{\left(m_{1} m_{2}\right)}{r^{2}} \]
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- Mass of Earth, \( m_1 = 5.972 \times 10^{24} \, \text{kg} \) - Gravitational constant, \( G = 6.674 \times 10^{-11} \, \text{N} \cdot \text{m}^2/\text{kg}^2 \) - Distance from the Earth, \( r = 1 \, \text{ft} \) Show more…
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Refer to the formula $F=\frac{G m_{1} m_{2}}{d^{2}}$. This gives the gravitational force $F$ (in Newtons, $N$ ) between two masses $m_{1}$ and $m_{2}$ (each measured in kg) that are a distance of $d$ meters apart. In the formula, $G=6.6726 \times 10^{-11} \mathrm{~N}-\mathrm{m}^{2} / \mathrm{kg}^{2}$. Determine the gravitational force between the Earth (mass $=5.98 \times 10^{24} \mathrm{~kg}$ ) and an $80-\mathrm{kg}$ human standing at sea level. The mean radius of the Earth is approximately $6.371 \times 10^{6} \mathrm{~m}$.
Review of Prerequisites
Integer Exponents and Scientific Notation
What is the force of gravity acting on an object at the Earth's surface? Earth's mass = 5.98 x 10^24 kg, object's mass = 1000 kg, the radius of the Earth is 6.38 x 10^6 m. Use the equation F = G * m1 * m2 / r^2.
Sri K.
Solve each problem. See Example 1. The gravitational force between two masses is given by $$F=\frac{G M m}{d^{2}}$$ Find $M$ to the nearest thousandth if $F=10, G=6.67 \times 10^{-11}, m=1,$ and $d=3 \times 10^{-6}$
Rational Expressions and Functions
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