00:02
Okay, nonlinear inequality, the solution using interval notation.
00:07
So for this first one, this one's actually the easiest one because it's already kind of solved for x.
00:15
So x is less than 2 or x is less than a negative 3.
00:22
So then you have negative 3 is less than x, which is less than 2.
00:28
So that's for a.
00:30
Then for this one, you have x is minus 6 times x plus 3 is less than or equal to 0.
00:39
So then you have x is greater than or equal to a positive 6 or x is less than or equal to a negative 3.
00:46
Then if i bring this one over to the other side, i have 2x plus squared plus x minus 1 is less than or equal to 0.
00:55
So then when i go and solve this, x is less than or equal to negative 1 or x is greater than or equal to 1 half.
01:05
And so that's the answer to c.
01:10
Just going to box off my answers.
01:12
Then for d, i'm going to bring this stuff over to the other side.
01:17
So i have x squared minus 3x minus 4 is less than 0.
01:24
So then i would go x minus 4 times x plus 1 is less than 0.
01:33
So then i have x is less than 4 or x is greater than a negative 1.
01:42
Then i'm going to multiply both sides by x minus 5.
01:49
So then i have 2x plus 1 is less than or equal to 3 times x minus 5.
01:57
So then i have 2x plus 1 is less than or equal to 3x minus 15.
02:04
So then i have negative x is less than or equal to negative 16.
02:09
So x is, i have to flip my inequality, is greater than or equal to the positive 16.
02:16
And then for f, i'll do f down here.
02:20
So i'm going to do 1 over 1 plus 2 over x plus 1 plus or actually minus 2 over x.
02:33
And so i'm going to set up common denominator of x times x plus 1.
02:44
And then x times x plus 1...