00:02
In this question we have given two sample cycles.
00:07
First is n1 is equal to 50 and n2 is equal to 100.
00:12
Now we have to find the relation between mean of this two standard deviation of these two and the shape of these two graphs.
00:23
So first, firstly this n1 represents number of samples selected.
00:32
Selected from population and this n2 represents possible sample for comparison.
00:56
So as we know that mean of the sampling distribution is same for both samples.
01:18
Samples that is n is equal to 50 and n is equals to 100 since we know that sample size does not affect the me now if we talk about the standard then standard deviation of sampling distribution when n1 is equal to 50 is given by standard deviation is equal to sigma divided by under root of n.
02:06
This is equal to sigma divided by under root of 50.
02:10
Now the standard deviation of sampling distribution when n2 is equals to 100 is standard deviation is equal to sigma divided by under root of end so it will be sigma divided by under root of 100 now here we can observe that as sample size increases the standard deviation decreases as it is inversely proportional now let us consider a situation that if the graph is normally distributed, then this is the main, this is the first standard deviation, and here it is a second 1 minus standard image...