00:01
In this question, it is given that 44 .8 liters of, in this question, it is given that 44 .8 liters of oxygen gas, that is o2 gas, at standard temperature and pressure.
00:28
The standard temperature is given as 273 .15 kelvin and standard pressure is 1 .013 times 10 rest of 5 pascal.
00:45
So by using the ideal gas equation, that is pb equal to nrt, here are the universal gas constant, from this we can find the value of n, that is number of modes, pv divided by rt.
01:11
So we can substitute the values, that is 1 .013 times 10 raised to 5 pascal, times the volume that is 44 .8 liters, and 1 litter is 10 raised to minus 3 meter cube.
01:28
So divided by r, that is 8 .3 .1 .3.
01:33
Joule per kelvin more times the temperature to 73 .15 kelvin and the number of moles can be calculated as 1 .998 moles so approximately it is equal to 2 .0 more then we know that one more contains 6 .0 to 2 .0 times 10 10 raise to 23 oxygen molecules.
02:12
So here we obtain 2 moles, that is n equal to 2 moles.
02:18
So the number of oxygen molecules, that is 2 into 6 .022 times 10 rise to 23 oxygen molecule...