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2) The fundamental vibrational frequency of the \( \mathrm{H}_{2} \) molecule is \( 4200 \mathrm{~cm}^{-1} \). Calculate the energy level spacing and the ZPE, in \( \mathrm{J} \) and in \( \mathrm{kJ} / \mathrm{mol} \). \[ \begin{array}{l} \mathrm{h}=1.05 \times 10^{-34} \mathrm{~J} \cdot \mathrm{s} \\ \mathrm{c}=3.00 \times 10^{8} \mathrm{~m} / \mathrm{s}=3.00 \times 1010 \mathrm{~cm} / \mathrm{s} \\ \mathrm{N}_{\mathrm{A}}=6.02 \times 1023 \mathrm{~mol}^{-1} \end{array} \]

          2) The fundamental vibrational frequency of the \( \mathrm{H}_{2} \) molecule is \( 4200 \mathrm{~cm}^{-1} \). Calculate the energy level spacing and the ZPE, in \( \mathrm{J} \) and in \( \mathrm{kJ} / \mathrm{mol} \).
\[
\begin{array}{l}
\mathrm{h}=1.05 \times 10^{-34} \mathrm{~J} \cdot \mathrm{s} \\
\mathrm{c}=3.00 \times 10^{8} \mathrm{~m} / \mathrm{s}=3.00 \times 1010 \mathrm{~cm} / \mathrm{s} \\
\mathrm{N}_{\mathrm{A}}=6.02 \times 1023 \mathrm{~mol}^{-1}
\end{array}
\]
        
Show more…
2) The fundamental vibrational frequency of the H2 molecule is 4200  cm^-1. Calculate the energy level spacing and the ZPE, in J and in kJ / mol.

    h=1.05 × 10^-34 J·s
        c=3.00 × 10^8 m / s=3.00 × 1010  cm / s
        NA=6.02 × 1023  mol^-1

Added by Hlala S.

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