2. The turnbuckle on cable AD is adjusted so that cable AD...

2. The turnbuckle on cable AD is adjusted so that cable AD applies a tensile force of 950 lb to point A. Determine the resulting tensions in cables AB and AC, and determine the compressive force applied by tower AE to point A. (Hint: When you draw a FBD of point A, all three cables pull on point A, and tower AE pushes on point A. Therefore, on the FBD of point A, all three cables will be pointed away from point A, but the vertical force applied by the tower to point A will be pushing on point A.)

Transcript

00:01 Hello everyone this problem is based on concept of forces in equilibrium so i am explaining the concept here for forces to be in equilibrium summation of all forces acting at a point must be zero so that concept we have to apply let us read the question in the question it is given the cable ad is tightened by a trunk buckle and deplet attention so tension in ad is given.

01:00 Tension in ad card is given 1300 pound.

01:09 We have to calculate the tension in av and ac.

01:16 We have to find the tension in av and ac so that force deploy along the antenna tower ae at point a.

01:31 The force is to be developed along in this direction.

01:47 So force develop along ae tower.

01:53 Like this we can also represent by force so it will be better so there will be a symmetry in writing nothing else so this is the force f -a -v f -a -v f -a -d f -a -v and f -a -c let us start solving it the force will develop in this direction let us see here force f -a -v in this direction i am marking with v -a -a -v -f -e -force this is f -a -v force this is f ac force.

02:33 I'm writing here fac force.

02:39 This is f ad force.

02:44 So all these forces has to be expressed.

02:49 This is f .a .e.

02:56 Force.

03:02 All these i have expressed in terms of unit vector i -cap, j -cap and k -cap by using the position vector.

03:12 So we have to write the position of all the points.

03:16 B, c, d, e and express the force in position vector format.

03:25 One by one i am writing, let us see here.

03:30 First i am writing the force f -a -v, you should follow the concept of vector, magnitude of f -a -b force to be multiplied with unit vector of a -v.

03:43 I am writing here the unit vector of a -v, magnitude of a -v force to be multiplied applied with unit vector a .b vector having 10 icap minus 15 g cap by using the coordinates you can easily form it divided by its magnitude.

04:06 So on solving its magnitude would be 35.

04:11 I'm writing directly...

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