Question

2- Three branch currents in a network are known to be i(t) = 2 sin(377t + 459) A, ix(t) = 0.5 cos(377t + 109) A, i3(t) = -0.25 sin(377t + 609) A. Determine the phase angles by which a) i(t) leads iz(t) b) i(t) leads is(t) [Answer: a) i1 leads i2 by 550 b) i leads is by 1659]

Name: 2 three branch currents in a network are known to be i t 2 sin 377t 459 a ixt 05 cos 377t 109 a i3t 025 sin 377t 609 a determine the phase angles by which a i t leads izt b i t leads ist an 33634
Uploaded: 2021-12-30T10:47:30-08:00
Duration: 6 min 21 s
Channel: Jagjit Singh Chander
Description: 2 three branch currents in a network are known to be i t 2 sin 377t 459 a ixt 05 cos 377t 109 a i3t 025 sin 377t 609 a determine the phase angles by which a i t leads izt b i t leads ist an 33634

          2- Three branch currents in a network are known to be i(t) = 2 sin(377t + 459) A, ix(t) = 0.5 cos(377t + 109) A, i3(t) = -0.25 sin(377t + 609) A. Determine the phase angles by which a) i(t) leads iz(t) b) i(t) leads is(t) [Answer: a) i1 leads i2 by 550 b) i leads is by 1659]

Added by Timothy Q.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Jagjit Singh Chander

12/30/2021

Step 1

Step 1: Find the phase angle by which i(t) leads ix(t): Given that the phase angle of i(t) is 52° and the phase angle of ix(t) is 100°, we can calculate the phase angle by which i(t) leads ix(t) as follows: $$\text{Phase angle} = 100° - 52° = 48°$$ Show more…

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2- Three branch currents in a network are known to be i(t) = 2 sin(377t + 459) A, ix(t) = 0.5 cos(377t + 109) A, i3(t) = -0.25 sin(377t + 609) A. Determine the phase angles by which a) i(t) leads iz(t) b) i(t) leads is(t) [Answer: a) i1 leads i2 by 550 b) i leads is by 1659]