00:01
First of all let's have a look what all is given in the problem.
00:03
Given is 500 ml of hcl solution is given.
00:07
This is the volume that is given and the molarity is given as 0 .1 molar.
00:11
Now it is given that you have 35 % of concentrated hcl and this is mass by mass percentage and the density of this is also given.
00:21
The density for this is given as 1 .2 gram per centimeter cube.
00:26
What you are supposed to find out is you need to find out the volume that will be required to prepare this solution so let's try to find out that first thing that we can do is we can calculate the number of moles so let's try to calculate the number of moles first so number of moles will be equal to molarity into volume molarity is 0 .1 and if we talk about this volume it's going to be 0 .5 so, it is equal to 0 .05 moles.
00:55
This is the number of moles that is required.
00:57
Now, we know that in 35 % means 100 gram of solution.
01:03
100 gram of solution contains 35 gram of solute.
01:07
35 gram of we can say that hcl.
01:10
Now, it is 0 .05 moles.
01:12
So, for this we can calculate the mass.
01:14
Mass is nothing but number of moles into molar mass...