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2) Two children, one with a mass of m1 = 20 kg, the other with a mass of m2 = 30 kg, sit on a see-saw. The pivot point (axis of rotation) is directly below the center of mass of the see-saw plank; the plank has a mass of 20 kg. a) The see-saw is in rotational equilibrium. Child one sits 1.5 m from the pivot point. Determine how far from the pivot point child two sits. b) The plank is moved so the center of mass of the plank is 0.75 m to the left of the pivot point as shown. Child one is still sitting 1.5 m from the pivot point. Determine how far from the pivot point child two sits now.

          2) Two children, one with a mass of m1 = 20 kg, the other with a mass of m2 = 30 kg, sit on a see-saw. The pivot point (axis of rotation) is directly below the center of mass of the see-saw plank; the plank has a mass of 20 kg.

a) The see-saw is in rotational equilibrium. Child one sits 1.5 m from the pivot point. Determine how far from the pivot point child two sits.

b) The plank is moved so the center of mass of the plank is 0.75 m to the left of the pivot point as shown. Child one is still sitting 1.5 m from the pivot point. Determine how far from the pivot point child two sits now.

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2) Two children, one with a mass of m1 = 20 kg, the other with a mass of m2 = 30 kg, sit on a see-saw. The pivot point (axis of rotation) is directly below the center of mass of the see-saw plank; the plank has a mass of 20 kg.

a) The see-saw is in rotational equilibrium. Child one sits 1.5 m from the pivot point. Determine how far from the pivot point child two sits.

b) The plank is moved so the center of mass of the plank is 0.75 m to the left of the pivot point as shown. Child one is still sitting 1.5 m from the pivot point. Determine how far from the pivot point child two sits now.

Added by David W.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Timothy James

04/18/2023

Step 1

Let's denote the distance of child two from the pivot point as $x_2$. The torque due to child one is $20\,\text{kg} \cdot 9.8\,\text{m/s}^2 \cdot 1.5\,\text{m} = 294\,\text{N}\cdot\text{m}$. The torque due to child two is $30\,\text{kg} \cdot 9.8\,\text{m/s}^2 Show more…

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2) Two children, one with a mass of 120kg and the other with a mass of 3kg, sit on a see-saw. The pivot point (axis of rotation) is directly below the center of mass of the see-saw plank, which has a mass of 20kg. a) The see-saw is in rotational equilibrium, and child one sits 1.5m from the pivot point. Determine how far from the pivot point child two sits. b) The plank is moved so that the center of mass of the plank is 0.75m to the left of the pivot point, as shown. Child one is still sitting 1.5m from the pivot point. Determine how far from the pivot point child two sits now. The mass of the plank is 20kg.

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