Question

2. Two thin lenses with a focal length of magnitude 13.0 cm , the first diverging and the second converging, are located 19.00cm apart. An object 1.80mm tall is placed 20.0cm to the left of the first (diverging) lens. How far from this first lens is the final image formed? Is the final image real or virtual? What is the height of the final image? Is it erect or inverted? Make drawing of a ray diagram.

          2. Two thin lenses with a focal length of magnitude 13.0 cm , the first diverging and the second converging, are located 19.00cm apart. An object 1.80mm tall is placed 20.0cm to the left of the first (diverging) lens.

How far from this first lens is the final image formed?
Is the final image real or virtual?
What is the height of the final image?
Is it erect or inverted?
Make drawing of a ray diagram.

2. Two thin lenses with a focal length of magnitude 13.0 cm , the first diverging and the second converging, are located 19.00cm apart. An object 1.80mm tall is placed 20.0cm to the left of the first (diverging) lens.

How far from this first lens is the final image formed?
Is the final image real or virtual?
What is the height of the final image?
Is it erect or inverted?
Make drawing of a ray diagram.

Added by Joana K.

University Physics with Modern Physics

Roger A. Freedman, Hugh D. Young 15th Edition

Chapter 34

Instant Answer

Solved by Expert Supratim Pal

12/17/2024

Step 1

- Focal length of the first (diverging) lens, \( f_1 = -13.0 \, \text{cm} \) - Focal length of the second (converging) lens, \( f_2 = 13.0 \, \text{cm} \) - Distance between the lenses, \( d = 19.0 \, \text{cm} \) - Object distance from the first lens, \( s_1 = Show more…

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