Base Case: For n=1, the left side is (2*1-1)^2 = 1 and the right side is 1*(2*1-1)*(2*1+1)/3 = 1. So, the base case holds.
Inductive Step: Assume the statement is true for n=k, i.e., \( \sum_{i=1}^{k}(2 i-1)^{2}=\frac{k(2 k-1)(2 k+1)}{3} \).
We need to prove it
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