What is the specific heat of a metal whose mass is 94.5 g if the temperature changes from 250°C to 48°C when it absorbs 850 J of heat?
Added by Pablo N.
Step 1
The change in temperature is the final temperature minus the initial temperature: ΔT = T_final - T_initial ΔT = 48°C - 250°C ΔT = -202°C Now, we can use the formula for heat transfer: Q = mcΔT where Q is the heat transfer (850 J), m is the mass (94.5 g), c is Show more…
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