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Hello everyone.
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In this question there is a reaction of 2e m plus a and it is giving us the product as e2ma.
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This is the overall reaction and in step 1 the reaction is e plus e is reacting and forming e2.
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In step 2 e2 is reacting further with m and it is giving us e2m in step 3 e2m.
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E to m is reacting with a and it is finally giving us e to m .a.
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Now we have to find out which one option will be the correct option.
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So our first option is m is a catalyst that inter as a reacting.
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So option a is wrong or incorrect because if m is a catalyst it must remove from the product side.
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If m is catalyst it can only consume.
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In reaction reaction but it must remove from the product right so option number is wrong and this is the rate determining step that is the slowest step and rate determining state rate determining step okay so let's see the option number b option number b saying that the order of m is zero and the rate of reaction is not dependent on the concentration of m.
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So here we can see that if this is k1 and this is k2, so for step 2 we can write the order of reaction or we can say the rate of reaction, rate of reaction will be equal to k2, concentration of m and concentration of e2...