Question

20 kW power is to be transmitted by a belt having mass density 1 g/cm^3 and 6 mm thickness. Calculate the width of the belt. The pulley rotates at 300 rpm and its diameter is 90 cm. The angle of contact is 180° and the coefficient of friction is 0.25. Take permissible stress as 210 N/cm².

Name: 20 kw power is to be transmitted by a belt having mass density 1 gcm3 and 6 mm thickness calculate the width of the belt the pulley rotates at 300 rpm and its diameter is 90 cm the angle of 11419
Uploaded: 2023-09-14T09:42:06-08:00
Duration: 2 min 27 s
Channel: Supreeta N
Description: 20 kw power is to be transmitted by a belt having mass density 1 gcm3 and 6 mm thickness calculate the width of the belt the pulley rotates at 300 rpm and its diameter is 90 cm the angle of 11419

          20 kW power is to be transmitted by a belt having mass density 1 g/cm^3 and 6 mm thickness. Calculate the width of the belt. The pulley rotates at 300 rpm and its diameter is 90 cm. The angle of contact is 180° and the coefficient of friction is 0.25. Take permissible stress as 210 N/cm².

Added by Marcos M.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supreeta N

09/14/2023

Step 1

Given power = 20 kW = 20,000 W Speed of pulley = 300 rpm = 300/60 = 5 rev/s Using the formula: Power = Tension * Velocity Tension = Power / Velocity Tension = 20,000 W / 5 rev/s Tension = 4,000 N Show more…

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20 kW power is to be transmitted by a belt having mass density 1 g/cm^3 and 6 mm thickness. Calculate the width of the belt. The pulley rotates at 300 rpm and its diameter is 90 cm. The angle of contact is 180° and the coefficient of friction is 0.25. Take permissible stress as 210 N/cm².