00:01
Hello students in this question, a c -sum as shown in the figure is been given whose pre -body diagram is shown on the right -hand side.
00:08
And in this question, it is given that mass of the board, capillator m is taken to be 5 kilogram, the length of the board, capillator l is taken to be 2 .4 meter.
00:20
The offset distance, which is taken as x offset, which can be represented as x in this case, is taken to be a value of 14 into 10 raise to minus 2 meter.
00:32
The mass on the right hand side is taken as m1 which is equal to 28 kilograms.
00:38
On the hand, mass of the left hand is taken as m2 which is equal to 62 kilogram.
00:44
And here from the pre -body diagram we can say that the weight of the board is taken as capillator w which is equal to mass of the board capillator m into acceleration due to gravity g.
00:56
On to the end, the weight on the right hand is taken as w1 which is equal to mass m1 into g.
01:03
And finally, the weight of the left hand side is taken as w2 which is equal to mass m2 into acceleration due to gravity g.
01:11
Now in the first part of the question, we need to find out the value of distance between the pivot and the center of the board which is taken as monoleter d.
01:20
And here from the freebody diagram we can say that the net torque which is taken as summation of to will be equal to the sum of torque in the left hand side which is taken as toe l plus torque on the right hand side to be equal to a value of zero...