00:01
In this question, there is a three force vector is given.
00:04
This is the c, this is the line, this is b vector, the angle is 60 degree, and there is another force, that is a vector, this is 20 degree.
00:19
So we are calculated the magnitude of the resultant force and direction of the resultant force.
00:27
So first of all, you can resolve this.
00:29
So we can write here this is a cost 20 degree and this is b plus 60 degree and here this is b sine 60 degree plus this is a sign 20 degree.
00:46
So the value of a this is equal to 4 .20 is given.
00:51
The value of b is 6 .91 and the value of c is 3 .48.
00:56
Let's find out the magnitude of resulted force because there are three force acted at the same point so force in x direction is b coss 60 degree minus a cost 20 degree so the value of b is 6 .91 this is 0 .5 so we can write here minus a that is 4 .20 cost 20 is 0 .939 so the force is in x direction is equal to minus 0 .4 -380 this is the force in x direction.
01:36
So negative means the direction of force is leftwards.
01:42
Similarly, we are calculated the force in by direction...